(2w^2-10w-28)/(w^2-3w-28)

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Solution for (2w^2-10w-28)/(w^2-3w-28) equation:


D( w )

w^2-(3*w)-28 = 0

w^2-(3*w)-28 = 0

w^2-(3*w)-28 = 0

w^2-3*w-28 = 0

w^2-3*w-28 = 0

DELTA = (-3)^2-(-28*1*4)

DELTA = 121

DELTA > 0

w = (121^(1/2)+3)/(1*2) or w = (3-121^(1/2))/(1*2)

w = 7 or w = -4

w in (-oo:-4) U (-4:7) U (7:+oo)

(2*w^2-(10*w)-28)/(w^2-(3*w)-28) = 0

(2*w^2-10*w-28)/(w^2-3*w-28) = 0

2*w^2-10*w-28 = 0

2*(w^2-5*w-14) = 0

w^2-5*w-14 = 0

DELTA = (-5)^2-(-14*1*4)

DELTA = 81

DELTA > 0

w = (81^(1/2)+5)/(1*2) or w = (5-81^(1/2))/(1*2)

w = 7 or w = -2

2*(w+2)*(w-7) = 0

w^2-3*w-28 = 0

w^2-3*w-28 = 0

DELTA = (-3)^2-(-28*1*4)

DELTA = 121

DELTA > 0

w = (121^(1/2)+3)/(1*2) or w = (3-121^(1/2))/(1*2)

w = 7 or w = -4

(w+4)*(w-7) = 0

(2*(w+2)*(w-7))/((w+4)*(w-7)) = 0

( 2 )

2 = 0

w belongs to the empty set

( w+2 )

w+2 = 0 // - 2

w = -2

( w-7 )

w-7 = 0 // + 7

w = 7

w in { 7}

w = -2

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